Added solution for ProjectEuler/025: php, ruby

This commit is contained in:
FuryFire
2012-03-30 11:15:23 +02:00
parent a858aaadda
commit 94dc7ec373
5 changed files with 83 additions and 25 deletions

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@ -5,7 +5,8 @@ desc: |
A permutation is an ordered arrangement of objects. For example, 3124 is one possible permutation of the digits 1, 2, 3 and 4. If all of the permutations are listed numerically or alphabetically, we call it lexicographic order. The lexicographic permutations of 0, 1 and 2 are:
012 021 102 120 201 210
What is the millionth lexicographic permutation of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9?
todo: Improve algorithm -
solution: Bruteforce
solutions:
solutions:
solve.php:
desc: Basic Solution
language: php

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@ -1,25 +1,26 @@
<?php
function fac($number) {
if($number == 1)
return 1;
return $number * fac($number-1);
}
$result = array(0,0,0,0,0,0,0,0,0,0);
define('NUM_PERMUTATION',1000000);
define('DIGITS',9);
$target = NUM_PERMUTATION - 1;
$endsteps = 1000000;
$cstep = 0;
$cdigit = 9;
while($cdigit != 0) {
do{
$result[9-$cdigit]++;
$cstep += fac($cdigit);
} while ($cstep < $endsteps) ;
echo "Done with $cdigit - steps:$cstep\n";
$cdigit--;
$digits = range(0, 9);
$permus = array(1 => 1);
for ($i = 2; $i <= 9; $i++) {
$permus[$i] = $permus[$i - 1] * $i;
}
echo "DONE!";
print_r($result);
echo " - ".$cstep ."\n";
echo "Result: 2783915460";
$permus = array_reverse($permus);
$values = array();
foreach ($permus as $n) {
$values[] = floor($target / $n);
$target = $target%$n;
}
$result = "";
foreach ($values as $val) {
$result .= $digits[$val];
unset($digits[$val]);
sort($digits);
}
$result .= $digits[0];
echo $result;