Added solution for ProjectEuler/025: php, ruby
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A permutation is an ordered arrangement of objects. For example, 3124 is one possible permutation of the digits 1, 2, 3 and 4. If all of the permutations are listed numerically or alphabetically, we call it lexicographic order. The lexicographic permutations of 0, 1 and 2 are:
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012 021 102 120 201 210
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What is the millionth lexicographic permutation of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9?
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todo: Improve algorithm -
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solution: Bruteforce
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solutions:
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solutions:
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solve.php:
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desc: Basic Solution
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language: php
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@ -1,25 +1,26 @@
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<?php
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function fac($number) {
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if($number == 1)
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return 1;
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return $number * fac($number-1);
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}
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$result = array(0,0,0,0,0,0,0,0,0,0);
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define('NUM_PERMUTATION',1000000);
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define('DIGITS',9);
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$target = NUM_PERMUTATION - 1;
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$endsteps = 1000000;
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$cstep = 0;
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$cdigit = 9;
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while($cdigit != 0) {
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do{
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$result[9-$cdigit]++;
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$cstep += fac($cdigit);
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} while ($cstep < $endsteps) ;
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echo "Done with $cdigit - steps:$cstep\n";
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$cdigit--;
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$digits = range(0, 9);
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$permus = array(1 => 1);
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for ($i = 2; $i <= 9; $i++) {
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$permus[$i] = $permus[$i - 1] * $i;
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}
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echo "DONE!";
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print_r($result);
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echo " - ".$cstep ."\n";
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echo "Result: 2783915460";
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$permus = array_reverse($permus);
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$values = array();
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foreach ($permus as $n) {
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$values[] = floor($target / $n);
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$target = $target%$n;
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}
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$result = "";
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foreach ($values as $val) {
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$result .= $digits[$val];
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unset($digits[$val]);
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sort($digits);
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}
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$result .= $digits[0];
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echo $result;
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