Restructuring

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2024-07-01 13:49:44 +00:00
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title: Finding Fibonacci numbers for which the first and last nine digits are pandigital.
url: http://projecteuler.net/problem=104
desc: |
The Fibonacci sequence is defined by the recurrence relation:
Fn = Fn1 + Fn2, where F1 = 1 and F2 = 1.
It turns out that F541, which contains 113 digits, is the first Fibonacci number for which the last nine digits are 1-9 pandigital (contain all the digits 1 to 9, but not necessarily in order). And F2749, which contains 575 digits, is the first Fibonacci number for which the first nine digits are 1-9 pandigital.
Given that Fk is the first Fibonacci number for which the first nine digits AND the last nine digits are 1-9 pandigital, find k.
solution: |
Bruteforce
solutions:
solve.php:
desc: Bruteforce - Sooooo slow
language: php

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<?php
function pandigital($num) {
for ($i = 1; $i <= 9; $i++) {
if(strpos($n,(string)$i) === false) {
return false;
}
}
return true;
}
$var = 1;
$k = 1;
while(true) {
$k++;
$new = bcadd($var,$prev);
$prev = $var;
$var = $new;
if(pandigital(substr($var,-9)) AND pandigital(substr($var,0,9))) { echo $k; die; }
}