Added solutions to Generic/FizzBuzz

Generic/FIZZBUZZ/desc.yml

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+title: FizzBuzz
+url: http://projecteuler.net/problem=1
+
+desc: |
+  The classical coding challenge. Write a program that prints the numbers from 1 to 100. But for multiples of three print <20>Fizz<7A> instead of the number and for the multiples of five print <20>Buzz<7A>. For numbers which are multiples of both three and five print <20>FizzBuzz<7A>.
+  
+solution: |
+  See the code...
+
+solutions:
+  solve.php:
+    desc: Basic solution
+    usage: 
+    language: php
+  solve.rb:
+    desc: Basic solution in Ruby
+    language: ruby
+  solve.c:
+    desc: ANSI C solution (Tested with TCC)
+    language: c

Generic/FIZZBUZZ/solve.c

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+#include <stdio.h>
+
+int main( )
+{
+	int i = 0;
+	for(i = 1; i <= 100; i++)
+	{
+		if(i % 3 == 0)
+		{
+			printf( "Fizz" );
+		}
+		if(i % 5 == 0)
+		{
+			printf( "Buzz" );
+		}
+		if(i % 3 && i % 5)
+		{
+			printf( "%d", i );
+		}
+		printf( "\n" );
+	}
+}

Generic/FIZZBUZZ/solve.php

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+<?php
+for($i=1; $i<=100; $i++) {
+	if($i % 3 == 0) {
+		print "Fizz";
+	}
+	if($i % 5 == 0) {
+		print "Buzz";
+	}
+	if($i % 3 AND $i % 5) {
+		print $i;
+	}
+	print PHP_EOL;
+}

Generic/FIZZBUZZ/solve.rb

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+(1..100).each do |i|
+	if(i % 3 == 0) 
+		print "Fizz";
+	end
+	if(i % 5 == 0) 
+		print "Buzz"
+	end
+	if(i % 3 != 0 and i % 5 != 0) 
+		print i
+	end
+	print "\n";
+end