title: Find the last ten digits of 11 + 22 + ... + 10001000.
url: http://projecteuler.net/problem=48

desc: |
  The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.
  Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
  
solution: |
  Bruteforce

solutions:
  solve.php:
    desc: Using BCMath to cope with large numbers
    language: php
  solve.rb:
    desc: Basic solution
    language: ruby
